We’re being asked to draw a Lewis structure for PF5. We first need to determine the total number of valence electrons present in the molecule:
Group Valence Electrons
P 5A 1 × 5 e– = 5 e–
F 7A 5 × 7 e– = 35 e–
Total: 40 valence e–
Make a sketch of PF5.
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