We’re being asked to draw a Lewis structure for ClF3. We first need to determine the total number of valence electrons present in the molecule:
Group Valence Electrons
Cl 7A 1 × 7 e– = 7 e–
F 7A 3 × 7 e– = 21 e–
Total: 28 valence e–
Draw the Lewis structure of ClF3.
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