Recall that shielding is the resistance of an electron from the attractive forces exerted by the nucleus.
Electrons that are further away from the nucleus have greater shielding. This means the orbital that experiences that greatest shielding is farthest from the nucleus.
We first need to determine the electron configuration of sulfur (S):
S belongs in the p-block in Period 3 so its electron configuration will end at the 3p subshell. Recall that the p–subshell can hold a maximum of 6 electrons. The atomic number of S is 16 so it has 16 electrons.
Which electron in sulfur is most shielded from nuclear charge?
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