🤓 Based on our data, we think this question is relevant for Professor Pierce's class at SPU.
The first thing we have to do for drawing the Lewis structure of C3H4 is to count the number of valence electrons.
Start with the carbons and put them in the center because H never goes in the center.
Let's just put 1 bond in between the carbons for starters. That will account for 4 e- (2 each bond)
The compound C3H4 has two double bonds.
Draw its Lewis structure.