🤓 Based on our data, we think this question is relevant for Professor Berghout & Davidson's class at WEBER.
Group Valence Electrons
C 4A 3 × 4 e– = 12 e–
H 1A 6 × 1 e– = 6 e–
Total: 18 valence e–
Determine the molecular geometry around each carbon atom located at the ends of the molecule CH2CHCH3, using VSEPR theory.