Ch.10 - Molecular Shapes & Valence Bond TheoryWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Select the correct hybridization for the central atom based on the electron geometry CCl4.

Solution: Select the correct hybridization for the central atom based on the electron geometry CCl4.

Problem

Select the correct hybridization for the central atom based on the electron geometry CCl4.

Solution

Orbital Hybridization is the concept of mixing of atomic orbitals into new hybrid orbitals that are capable of pairing electrons to form chemical bonds.


Hybridization


Groups attached to the central atom. (Lone pairs and surrounding elements)

Electronic Geometry

sp

1 + 1 = 

2

linear

sp2

1 + 2 =

3

trigonal planar

sp3

1 + 3 =

4

tetrahedral

sp3d

1 + 3 + 1 =

5

trigonal bi-pyramidal

sp3d2

1 + 3 + 2 =

6

octahedral








Each group attached or a lone pair can be considered as 1.

We can determine the hybridization of the central atom of CCl4 through its electron geometry.


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