$\mathbf{E}\mathbf{=}\mathbf{h\nu}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\frac{\mathbf{c}}{\mathbf{\lambda}}\mathbf{=}\frac{\overline{)\mathbf{\lambda}}\mathbf{\xb7}\mathbf{\nu}}{\overline{)\mathbf{\nu}}}\phantom{\rule{0ex}{0ex}}\mathbf{\nu}\mathbf{=}\frac{\mathbf{c}}{\mathbf{\lambda}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\overline{)\mathbf{E}\mathbf{=}\frac{\mathbf{hc}}{\mathbf{\lambda}}}$

$\mathbf{\lambda}\mathbf{=}\mathbf{155}\mathbf{}\overline{)\mathbf{nm}}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{9}}\mathbf{}\mathbf{m}}{\mathbf{1}\mathbf{}\overline{)\mathbf{nm}}}$

**λ = 1.55x10 ^{-7} m**

**Calculate Energy:**

Determine the energy of 1.60 mol of photons for each of the following kinds of light. (Assume three significant figures.)

ultraviolet radiation (155 nm)

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