Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The Hg2+ ion forms complex ions with I - as follows:Hg2+(aq) + I -(aq) ⇌ HgI+(aq)            K = 1.0 X 108 HgI+(aq) + I -(aq) ⇌ HgI2(aq)            K 2 = 1.0 X 105 HgI2(aq) + I -(aq) ⇌ HgI3-(aq)           K 3 = 1.0 X 109 HgI3-(aq) + I -(aq) ⇌ HgI42-(aq)         K 4 = 1.0 X 108A solution is prepared by dissolving 0.088 mole of Hg(NO3)2 and 5.00 moles of NaI in enough water to make 1.0 L of solution.b. Calculate the equilibrium concentration of [I -].

Solution: The Hg2+ ion forms complex ions with I - as follows:Hg2+(aq) + I -(aq) ⇌ HgI+(aq)            K 1 = 1.0 X 108HgI+(aq) + I -(aq) ⇌ HgI2(aq)            K 2 = 1.0 X 105HgI2(aq) + I -(aq) ⇌ HgI3-(aq)     

Problem

The Hg2+ ion forms complex ions with I - as follows:

Hg2+(aq) + I -(aq) ⇌ HgI+(aq)            K = 1.0 X 108
HgI+(aq) + I -(aq) ⇌ HgI2(aq)            K 2 = 1.0 X 105
HgI2(aq) + I -(aq) ⇌ HgI3-(aq)           K 3 = 1.0 X 109
HgI3-(aq) + I -(aq) ⇌ HgI42-(aq)         K 4 = 1.0 X 108

A solution is prepared by dissolving 0.088 mole of Hg(NO3)2 and 5.00 moles of NaI in enough water to make 1.0 L of solution.

b. Calculate the equilibrium concentration of [I -].