Ch.16 - Aqueous Equilibrium WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The equilibrium constant for the following reaction is 1.0 X 10 23:Cr3+(aq) + H2EDTA2-(aq) ⇌ CrEDTA-(aq) + 2H+(aq)EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually co

Problem

The equilibrium constant for the following reaction is 1.0 X 10 23:
Cr3+(aq) + H2EDTA2-(aq) ⇌ CrEDTA-(aq) + 2H+(aq)

EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt Na2H2EDTA, are used to treat heavy metal poisoning. Calculate [Cr3+] at equilibrium in a solution originally 0.0010 M in Cr3+ and 0.050 M in H2EDTA2- and buffered at pH = 6.00.