Problem: Kf for the complex ion Ag(NH3)2+ is 1.7 X 107. Ksp for AgCl is 1.6 X 10 -10. Calculate the molar solubility of AgCl in 1.0 M NH3.

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Step 1:

Step 2:

AgCl (s)  Ag+ (aq) + Cl- (aq)

Ksp = [Ag+][Cl-]

Ag+ (aq) + 2 NH3+ (aq)  [Ag(NH3)2+] (aq)

Kf =[AgNH32+][Ag+][NH3]2

AgCl (s) + NH3 (aq)  Cl- (aq) + Ag(NH3)2+ (aq)

K = [AgNH32+][Cl-][NH3]2K = Ksp×Kf =[Ag(NH3)2+][Cl-][NH3]2


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Problem Details

Kf for the complex ion Ag(NH3)2+ is 1.7 X 107. Ksp for AgCl is 1.6 X 10 -10. Calculate the molar solubility of AgCl in 1.0 M NH3.

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Based on our data, we think this problem is relevant for Professor Carlon's class at UCB.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.