Problem: In the presence of CN -, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 X 10 -40 M and 1.5 X 10 -3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)63-.Fe3+(aq) + 6CN -(aq) ⇋ Fe(CN)63-(aq)       Koverall = ?

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K =productreactantKoverall = [FeCN63-][Fe3+][CN-]6


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Problem Details

In the presence of CN -, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 X 10 -40 M and 1.5 X 10 -3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)63-.

Fe3+(aq) + 6CN -(aq) ⇋ Fe(CN)63-(aq)       Koverall = ?

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Our tutors have indicated that to solve this problem you will need to apply the Formation Constant concept. If you need more Formation Constant practice, you can also practice Formation Constant practice problems.

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Based on our data, we think this problem is relevant for Professor Leipzig's class at UW-SEATTLE.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.