In the presence of CN -, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 X 10 -40 M and 1.5 X 10 -3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)63-.
Fe3+(aq) + 6CN -(aq) ⇋ Fe(CN)63-(aq) Koverall = ?
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