Problem: In the presence of CN -, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 X 10 -40 M and 1.5 X 10 -3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)63-.Fe3+(aq) + 6CN -(aq) ⇋ Fe(CN)63-(aq)       Koverall = ?

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K =productreactantKoverall = [FeCN63-][Fe3+][CN-]6


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In the presence of CN -, Fe3+ forms the complex ion Fe(CN)63-. The equilibrium concentrations of Fe3+ and Fe(CN)63- are 8.5 X 10 -40 M and 1.5 X 10 -3 M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)63-.

Fe3+(aq) + 6CN -(aq) ⇋ Fe(CN)63-(aq)       Koverall = ?

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Based on our data, we think this problem is relevant for Professor Leipzig's class at UW-SEATTLE.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.