Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Highly toxic disulfur decafluoride decomposes by a freeradical process: S 2F10(g) ⥫⥬ SF4(g) + SF6(g). In a study of the decomposition, S 2F10 was placed in a 2.0-L flask and heated to 100°C; [S 2F10]

Problem

Highly toxic disulfur decafluoride decomposes by a freeradical process: S 2F10(g) ⥫⥬ SF4(g) + SF6(g). In a study of the decomposition, S 2F10 was placed in a 2.0-L flask and heated to 100°C; [S 2F10] was 0.50 M at equilibrium. More S 2F10 was added, and when equilibrium was reattained, [S2F10] was 2.5 M. How did [SF4] and [SF6] change from the original to the new equilibrium position after the addition of more S2F10?