The Reaction Quotient Video Lessons

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Problem: When 0.100 mol of CaCO3(s) and 0.100 mol of CaO(s) are placed in an evacuated sealed 10.0-L container and heated to 385 K, PCO2 = 0.220 atm after equilibrium is established:   CaCO3(s) ⇌ CaO(s) + CO2(g) An additional 0.300 atm of CO2(g) is pumped in. What is the total mass (in g) of CaCO 3 after equilibrium is re-established?

FREE Expert Solution

Step 1. Calculate for the molarity of CO2 at equilibrium

PV = nRTn =PVRT=(0.22 atm)(10 L)(0.08206 L atmmol K)(385K)n = 0.0696 molM = mol of soluteL solutionM = 0.0696 mol10 L=0.00696 M


Step 2. Setup the Keq expression

Recall that the equilibrium constant is the ratio of the products and reactants.  We use Kp when dealing with pressure and Kc when dealing with concentration:


Kp=PproductsPreactantsKp = CO2



Recall CaCO3 and CaO are not included in the Kp expression since they are both in solid state


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Problem Details

When 0.100 mol of CaCO3(s) and 0.100 mol of CaO(s) are placed in an evacuated sealed 10.0-L container and heated to 385 K, PCO2 = 0.220 atm after equilibrium is established:   

CaCO3(s) ⇌ CaO(s) + CO2(g) 

An additional 0.300 atm of CO2(g) is pumped in. What is the total mass (in g) of CaCO 3 after equilibrium is re-established?

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Our tutors have indicated that to solve this problem you will need to apply the The Reaction Quotient concept. You can view video lessons to learn The Reaction Quotient. Or if you need more The Reaction Quotient practice, you can also practice The Reaction Quotient practice problems.

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Based on our data, we think this problem is relevant for Professor Heiden's class at Michigan Technological University.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.