Problem: In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb = 4.4 x 10-4), with 0.50 M HCl, calculate the pH under the following conditions.a. after 50.0 mL of 0.50 M HCl has been added

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FREE Expert Solution

(1) Calculated moles of w.base and s.acid

mol CH3NH2 =50 mL 1x10-3 L1 mL1 mol1 L

mol CH3NH2 = 0.05 mol

mol HCl =50 mL 1x10-3 L1 mL0.5 mol1 L

mol HCl = 0.025 mol


(2) Construct an ICF chart:

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Problem Details

In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb = 4.4 x 10-4), with 0.50 M HCl, calculate the pH under the following conditions.

a. after 50.0 mL of 0.50 M HCl has been added