🤓 Based on our data, we think this question is relevant for Professor Du's class at UGA.
(1) Calculated moles of w.base and s.acid
mol CH3NH2 = 0.05 mol
mol HCl = 0.025 mol
(2) Construct an ICF chart:
In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb = 4.4 x 10-4), with 0.50 M HCl, calculate the pH under the following conditions.
a. after 50.0 mL of 0.50 M HCl has been added