Given titration: Ba(OH)2(aq) + HCl(aq) → BaCl2(aq) + H2O(l) → Strong Base + Strong Acid
Volume of HCl added = 0.0 mL → initial pH of the solution
Consider the titration of 80.0 mL of 0.100 M Ba(OH) 2 by 0.400 M HCl. Calculate the pH of the resulting solution after the following volumes of HCl have been added.
a. 0.0 mL
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