Problem: Calculate the pH of each of the following solutions.b. 0.100 M HONH3Cl

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FREE Expert Solution

HONH3Cl (aq) → HONH3+ (aq) + Cl- (aq) 

Reaction produces an acidic species:

Kb of HONH2 → 9.1x10-9 

(1) Setup an ICE chart:

(2) Setup Ka expression

Ka=productsreactants=[H3O+][Al(H2O)52+][Al(H2O)63+]


Solving for x = [H3O+]


Ka = KwKb=1x10-149.1x10-9=1.099x10-6Ka=1.099x10-6=[H3O+][HONH2][HONH3+]1.099x10-6=[x][x][0.1 - x], ignore -x:[HONH2]iKa>5001.099x10-6(0.1)=x2x = 1.099x10-6(0.1)


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Problem Details

Calculate the pH of each of the following solutions.

b. 0.100 M HONH3Cl

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Based on our data, we think this problem is relevant for Professor Vartia's class at KU.

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.