# Problem: Perform these calculations for nickel(II) carbonate. (b) If the NiCO3 were a contaminant in a sample of CoCO3 (Ksp = 1.0 × 10–12), what mass of CoCO3 would have been lost? Keep in mind that both NiCO3 and CoCO3 dissolve in the same solution.

###### FREE Expert Solution

We're being asked to calculate the mass of CoCO3 that would have been lost. Both NiCO3 and CoCO3 dissolve in the same solution.

The sulfate ion, CO32–, has a charge of –2. So the charge of Cobalt is +2:

NiCO3(s)  Co2+(aq) + CO32–(aq)

The sulfate ion, SO42–, has a charge of –2. So the charge of Nickel is +2:

CoCO3(s)  Co2+(aq) + CO32–(aq)

Notice that there is a common ion present, CO32–. The common ion effect states that the solubility of a salt is lower in the presence of a common ion.

We can construct an ICE table for the dissociation of CoCO3. Remember that solids are ignored in the ICE table.

***From Part A of this problem, we also calculated that the concentration of CO32– at equilibrium is 3.6878×10–4 M.

79% (98 ratings) ###### Problem Details

Perform these calculations for nickel(II) carbonate.

(b) If the NiCO3 were a contaminant in a sample of CoCO3 (Ksp = 1.0 × 10–12), what mass of CoCO3 would have been lost? Keep in mind that both NiCO3 and CoCO3 dissolve in the same solution.

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