Reaction: HONH2(aq) + HCl(aq) ⇌ HONH3+(aq) + H2O(l)
HONH3+(aq) + H2O(l) ⇌ HONH2(aq) + H3O+(aq)
Solve for x:
Calculate the pH after 0.020 mole of HCl is added to 1.00 L of each of the following solutions:
a. 0.100 M HONH2 (Kb = 1.1 x 10-8)
b. 0.100 M HONH3Cl
c. pure H2O
d. a mixture containing 0.100 M HONH2 and 0.100 M HONH3Cl
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