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Given: Kc = 1.8×10−56
T = 570. K
3O2(g) ⇌ 2O3(g)
reactants = 3 mol O2(g)
reactants = 3 moles gas
products = 2 mol O3(g)
products = 2 moles gas
Δn = 3 mol – 2 mol
Δn = 1 mol
Calculate Kp for the following equilibria:
(b) 3O2(g) ⇌ 2O3(g); Kc = 1.8×10−56 at 570. K
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