# Problem: Calculate Kc for the following equilibria:(a) CO(g) + Cl2(g) ⥫⥬ COCl2(g); Kp = 3.9×10−2 at 1000. K

###### FREE Expert Solution

Kp and Kc are related to one another by the following equation below:

$\overline{){{\mathbf{K}}}_{{\mathbf{p}}}{\mathbf{=}}{{\mathbf{K}}}_{{\mathbf{c}}}{\left(\mathbf{RT}\right)}^{\mathbf{∆}\mathbf{n}}}$

R = gas constant = 0.08206 (Latm)/(molK)
T = temperature, K
Δn = moles of gas products – moles of gas reactants

Calculate c:

Given:                        Kp = 3.9×10-2

T = 1000 K

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Reaction:

CO(g) + Cl2(g) ⥫⥬ COCl2(g)

reactants = 1 mol CO(g) + 1 mol Cl2(g)
reactants = 2 moles gas

products = 1 mol COCl2(g)
products = 1 mole gas

Δn = 2 mol – 1 mol
Δn = 1 mol

82% (271 ratings) ###### Problem Details

Calculate Kc for the following equilibria:

(a) CO(g) + Cl2(g) ⥫⥬ COCl2(g); Kp = 3.9×10−2 at 1000. K

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