• HF is a weak acid
• the anion in NaF is the conjugate base
▪ F- → anion → conjugate base
- concentration of F- = concentration of NaF
weak acid + conjugate base = buffer
Step 1: Calculate pKa
Ka of HF = 7.24 x 10-4 (can be found in books or online)
pKa = 3.140
Step 2: Calculate pH
pH = 3.638
Step 3: Calculate the concentration of NaF.
Conjugate base = [F-] = [NaF]
Weak acid = [HF] = 0.300 M
What concentration of NaF is required to make [H3O+] = 2.3 × 10−4 in a 0.300-M solution of HF?
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