Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
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Ch.10 - Molecular Shapes & Valence Bond Theory
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Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
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Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: From the equilibrium concentration given, calculate K a for the weak acid and K b for the weak base.(d) C6 H5 NH3 + : [C6 H5 NH3 +] = 0.233 M;                        [C  6H5NH2]         = 2.3 × 10 −3

Problem

From the equilibrium concentration given, calculate K a for the weak acid and K b for the weak base.

(d) C6 H5 NH3 + : [C6 H5 NH3 +] = 0.233 M;
                        [C  6H5NH2]         = 2.3 × 10 −3 M;
                           [H  3 O+]            = 2.3 × 10 −3 M