Target reaction → NaO(g) + Na2O(s) ⇌ Na2O2(s) + Na(l)
NaO(g) ⇌ Na(l) + 1/2 O2(g) K2 = 2x10-5 → multiply equation by 2 → square
2 NaO(g) ⇌ 2 Na(l) + 2 O2(g) K2 = (2x10-5)2 = 4x10-10
Na2O2(s) ⇌ 2Na(l) + O2(g) K3 = 5x10-29 → reverse → take the reciprocal
2Na(l) + O2(g) ⇌ Na2O2(s) K3-1 = 1/5x10-29 = 2x1028
Given the following equilibrium constants at 427ºC,
Na2O(s) ⇌ 2Na(l) + 1/2 O2(g) K 1 = 2 x 10 -25
NaO(g) ⇌ Na(l) + 1/2 O2(g) K 2 = 2 x 10 -5
Na2O2(s) ⇌ 2Na(l) + O2(g) K 3 = 5 x 10 -29
NaO2(s) ⇌ Na(l) + O2(g) K 4 = 3 x 10 -14
determine the values for the equilibrium constants for the following reactions:
b. NaO(g) + Na2O(s) ⇌ Na2O2(s) + Na(l)
(Hint: When reaction equations are added, the equilibrium expressions are multiplied.)
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