Ch.14 - Chemical EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
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Ch.10 - Molecular Shapes & Valence Bond Theory
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Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Sections
Chemical Equilibrium
ICE Chart
Le Chatelier's Principle
The Reaction Quotient
Additional Guides
Equilibrium Expressions
LearnAdditional PracticeSummary

Solution: The following equilibrium pressures were observed at a certain temperature for the reactionN2(g) + 3H2(g) ⇌ 2NH3(g)PNH3 = 3.1 x 10 -2 atmPN2 = 8.5 x 10 -1 atmPH2 = 3.1 x 10 -3 atmCalculate the value for the equilibrium constant Kp at this temperature.If PN2 = 0.525 atm, PNH3 = 0.0167 atm, and PH2 = 0.00761 atm, does this represent a system at equilibrium?

Solution: The following equilibrium pressures were observed at a certain temperature for the reactionN2(g) + 3H2(g) ⇌ 2NH3(g)PNH3 = 3.1 x 10 -2 atmPN2 = 8.5 x 10 -1 atmPH2 = 3.1 x 10 -3 atmCalculate the value f

Problem

The following equilibrium pressures were observed at a certain temperature for the reaction

N2(g) + 3H2(g) ⇌ 2NH3(g)

PNH3 = 3.1 x 10 -2 atm

PN2 = 8.5 x 10 -1 atm

PH2 = 3.1 x 10 -3 atm

Calculate the value for the equilibrium constant Kp at this temperature.

If PN2 = 0.525 atm, PNH3 = 0.0167 atm, and PH2 = 0.00761 atm, does this represent a system at equilibrium?

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