Problem: For the reactionH2(g) + Br2(g) ⇌ 2HBr(g)              Kp = 3.5 x 104 at 1495 K. What is the value of Kp for the following reactions at 1495 K?a. HBr(g) ⇌ 1/2 H2(g) + 1/2 Br2(g)

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Required reaction:             HBr(g) ½ H2(g) + ½ Br2(g)

Given reaction:                   H2(g) + Br2(g) 2 HBr(g)              


Reverse reaction:               2 HBr(g) H2(g) + Br2(g)

Get reciprocal of Kp:         (1/Kp)

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Problem Details

For the reaction

H2(g) + Br2(g) ⇌ 2HBr(g)              Kp = 3.5 x 104 at 1495 K. 

What is the value of Kp for the following reactions at 1495 K?

a. HBr(g) ⇌ 1/2 H2(g) + 1/2 Br2(g)

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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.