Required reaction: HBr(g) ⇌ ½ H2(g) + ½ Br2(g)
Given reaction: H2(g) + Br2(g) ⇌ 2 HBr(g)
Reverse reaction: 2 HBr(g) ⇌ H2(g) + Br2(g)
Get reciprocal of Kp: (1/Kp)
For the reaction
H2(g) + Br2(g) ⇌ 2HBr(g) Kp = 3.5 x 104 at 1495 K.
What is the value of Kp for the following reactions at 1495 K?
a. HBr(g) ⇌ 1/2 H2(g) + 1/2 Br2(g)
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Our tutors have indicated that to solve this problem you will need to apply the Chemical Equilibrium concept. You can view video lessons to learn Chemical Equilibrium. Or if you need more Chemical Equilibrium practice, you can also practice Chemical Equilibrium practice problems.
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.