🤓 Based on our data, we think this question is relevant for Professor Telesford's class at TTU.
When a reaction mechanism is given, the rate law can be determined using the slow step in the reaction mechanism.
▪rate law only involves the reactants
▪ the coefficients of the reactants in the slow step are the order of the reaction with respect to that reactant
▪ Rate Law has a general form of:
2H2SO4⟶ H 3 O + + HSO4 - + SO3 [fast]
SO 3 + C6H6⟶ H(C6H5+)SO3 - [slow]
H(C6H5+)SO3- + HSO 4-⟶ C6H5SO3- + H2SO4 [fast]
C6H5SO3 - + H3O +⟶ C6H5SO3H + H2O [fast]
Sulfonation of benzene has the following mechanism:
(1) 2H2SO4 ⟶ H3O+ + HSO4- + SO3 [fast]
(2) SO3 + C6H6 ⟶ H(C6H5+)SO3- [slow]
(3) H(C6H5+)SO3- + HSO4- ⟶ C6H5SO3- + H2SO4 [fast]
(4) C6H5SO3- + H3O+ ⟶ C6H5SO3H + H2O [fast]
(b) Write the overall rate law in terms of the initial rate of the reaction.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Reaction Mechanism concept. If you need more Reaction Mechanism practice, you can also practice Reaction Mechanism practice problems.
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Based on our data, we think this problem is relevant for Professor Telesford's class at TTU.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.