Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Sodium sulfate 10−hydrate, Na 2SO4∙10H2O, dehydrates according to the equationNa2SO4·10H2O(s) ⇌ Na2SO4(s) + 10H2O(g)        K P = 4.08 x 10−25 at 25°CWhat is the pressure of water vapor at equilibrium with a mixture of Na  2SO4∙10H2O and NaSO4?

Problem

Sodium sulfate 10−hydrate, Na 2SO4∙10H2O, dehydrates according to the equation

Na2SO4·10H2O(s) ⇌ Na2SO4(s) + 10H2O(g)        K P = 4.08 x 10−25 at 25°C

What is the pressure of water vapor at equilibrium with a mixture of Na  2SO4∙10H2O and NaSO4?