Ch.13 - Chemical KineticsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Reactions between certain haloalkanes (alkyl halides) and water produce alcohols. Consider the overall reaction for t-butyl bromide (2-bromo-2-methylpropane):(CH3)3CBr(aq) + H2O(l) ⟶ (CH3)3COH(aq) + H

Problem

Reactions between certain haloalkanes (alkyl halides) and water produce alcohols. Consider the overall reaction for t-butyl bromide (2-bromo-2-methylpropane):

(CH3)3CBr(aq) + H2O(l) ⟶ (CH3)3COH(aq) + H+(aq) + Br-(aq)

The experimental rate law is rate = k[(CH3)3CBr]. The accepted mechanism for the reaction is

(1) (CH3)3C—Br(aq) ⟶ (CH3)3C+(aq) + Br-(aq)                      [slow]
(2) (CH3)3C+(aq) + H2O(l) ⟶ (CH3)3C—OH2+(aq)                [fast]
(3) (CH3)3C—OH2+(aq) ⟶ H+(aq) + (CH3)3C—OH(aq)         [fast]

(b) Write rate laws for the elementary steps.