Ch.14 - Chemical EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Equilibrium Expressions

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Sections
Chemical Equilibrium
ICE Chart
Le Chatelier's Principle
The Reaction Quotient
Additional Practice
Equilibrium Expressions

Solution: What is the value of the equilibrium constant at 500 °C for the formation of NH  3 according to the following equation?N2(g) + 3H2(g) ⇌ 2NH3(g)An equilibrium mixture of NH3(g), H2(g), and N2(g) at 500

Solution: What is the value of the equilibrium constant at 500 °C for the formation of NH  3 according to the following equation?N2(g) + 3H2(g) ⇌ 2NH3(g)An equilibrium mixture of NH3(g), H2(g), and N2(g) at 500

Problem

What is the value of the equilibrium constant at 500 °C for the formation of NH  3 according to the following equation?

N2(g) + 3H2(g) ⇌ 2NH3(g)

An equilibrium mixture of NH3(g), H2(g), and N2(g) at 500 °C was found to contain 1.35 M H 2, 1.15 M N2, and 4.12 × 10−1 M NH3.

Solution

We’re being asked to determine the equilibrium constant at 500˚C for this reaction:

N2(g) + 3 H2(g)  2 NH3(g)


Recall that the equilibrium constant is the ratio of the products and reactants

We use Kp when dealing with pressure and Kc when dealing with concentration:


Kp=PproductsPreactants     Kc=[products][reactants]


Note that solid and liquid compounds are ignored in the equilibrium expression.


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