Problem: If the gas inside the flask is cooled so that its pressure is reduced from 797.3 torr to a value of 715.7 torr what will be the height of the mercury in the open-end arm? (Hint: The sum of the heights in both arms must remain constant regardless of the change in pressure.)

🤓 Based on our data, we think this question is relevant for Professor Williams' class at GS.

FREE Expert Solution
  • Recall that when the height of the gas in an open end arm is higher compared to the one next to the gas: 

  • Pinitial = Patm + height difference (Pgas = Pinitial)

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Problem Details

If the gas inside the flask is cooled so that its pressure is reduced from 797.3 torr to a value of 715.7 torr what will be the height of the mercury in the open-end arm? (Hint: The sum of the heights in both arms must remain constant regardless of the change in pressure.)
An apparatus consists of a flask attached to a U-shaped tube containing mercury. The U-shaped tube is open at the end opposite the flask. Atmospheric pressure (P atm) exerts a downward force on the open end of the tube.  Gas in the flask (Pgas) enters the U-shaped tube and exerts a force on the mercury in the U-shaped tube; the mercury is higher on the open ended side. The difference in the height in mercury between the flask side of the U–shaped tube and the open ended side is h. The difference between the tallest height of mercury, on the open-ended side of the tube, and the bottom of the U is 136.4 millimeters. The difference between the lowest level of mercury (on the flask side of the U) and the bottom of the U is 103.8 millimeters. P gas equals P atm plus P h.