All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: At constant pressure, the mean free path (λ) of a gas molecule is directly proportional to temperature (T). At constant temperature, {lambda} is inversely proportional to pressure (P). If you compare

Problem

At constant pressure, the mean free path (λ) of a gas molecule is directly proportional to temperature (T). At constant temperature, is inversely proportional to pressure (P). If you compare two different gas molecules at the same temperature and pressure, is inversely proportional to the square of the diameter (d) of the gas molecules. Put these facts together to create a formula for the mean free path of a gas molecule with a proportionality constant (call it  Rmfp , like the ideal-gas constant).