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Problem: Gaseous iodine pentafluoride, IF5, can be prepared by the reaction of solid iodine and gaseous fluorine:I2 (s) + 5 F2(g) → 2 IF5 (g)A 5.10-L flask containing 10.2 g I2 is charged with 10.2 g F2, and the reaction proceeds until one of the reagents is completely consumed. After the reaction is complete, the temperature in the flask is 125oC.What is the partial pressure of IF5 in the flask?

FREE Expert Solution

(1) Find the limiting reactant

MM of I2 = 253.8 g/mol

MM of F2 = 38.0 g/mol

mol IF5 = 10.2 g I2 (1 mol I2253.8 g)(2 mol IF51 mol I2)

mol IF5 = 0.0804 mol IF5

mol IF5 = 10.2 g F2 (1 mol F238 g)(2 mol IF55 mol F2)

mol IF5 = 0.1074 mol IF5

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Problem Details

Gaseous iodine pentafluoride, IF5, can be prepared by the reaction of solid iodine and gaseous fluorine:
I2 (s) + 5 F2(g) → 2 IF5 (g)
A 5.10-L flask containing 10.2 g I2 is charged with 10.2 g F2, and the reaction proceeds until one of the reagents is completely consumed. After the reaction is complete, the temperature in the flask is 125oC.

What is the partial pressure of IF5 in the flask?

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