# Problem: Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):NH3(g) + HCl(g) → NH4Cl(s)Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawingOne flask contains 5.60g NH3(g), and the other contains 4.60 g  HCl(g). When the stopcock is opened, the gases react until one is completely consumed.What mass of ammonium chloride will be formed?

###### FREE Expert Solution

Step 1

= 0.3288 mol NH4Cl

= 0.1262 mol NH4Cl

HCl → limiting reactant

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###### Problem Details

Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):
NH3(g) + HCl(g) → NH4Cl(s)
Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawing

One flask contains 5.60g NH3(g), and the other contains 4.60 g  HCl(g). When the stopcock is opened, the gases react until one is completely consumed.

What mass of ammonium chloride will be formed?

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