= 0.3288 mol NH4Cl
= 0.1262 mol NH4Cl
HCl → limiting reactant
Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):
NH3(g) + HCl(g) → NH4Cl(s)
Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawing
One flask contains 5.60g NH3(g), and the other contains 4.60 g HCl(g). When the stopcock is opened, the gases react until one is completely consumed.
What mass of ammonium chloride will be formed?
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