Problem: Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):NH3(g) + HCl(g) → NH4Cl(s)Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawingOne flask contains 5.60g NH3(g), and the other contains 4.60 g  HCl(g). When the stopcock is opened, the gases react until one is completely consumed.Which gas will remain in the system after the reaction is complete?

FREE Expert Solution

Determine which is the limiting reactant and the excess reactant by calculating how much product each reactant can produce.

The reactant that produces lesser amount of product is the limiting reactant.

Balanced Reaction: NH3(g) + HCl(g) → NH4Cl(s)

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Problem Details

Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):
NH3(g) + HCl(g) → NH4Cl(s)
Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawing

Two gas flasks are connected by a tube with a stopcock. NH3 is in the flask on the left and HCl is in the flask on the right.

One flask contains 5.60g NH3(g), and the other contains 4.60 g  HCl(g). When the stopcock is opened, the gases react until one is completely consumed.

Which gas will remain in the system after the reaction is complete?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. You can view video lessons to learn Limiting Reagent. Or if you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.

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Based on our data, we think this problem is relevant for Professor Marin's class at UCF.