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| Naming Ionic Compounds | 36 mins | 0 completed | Learn |
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| Ionic and Covalent Bonds |
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| Limiting Reagent |
| Percent Yield |
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| Balancing Chemical Equations Worksheet |
| Theoretical Yield |
| Limiting Reactant |
Solution: Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):NH3(g) + HCl(g) → NH4Cl(s)Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawingOne flask contains 5.60g NH3(g), and the other contains 4.60 g HCl(g). When the stopcock is opened, the gases react until one is completely consumed.Which gas will remain in the system after the reaction is complete?
Problem
Ammonia, NH3(g), and hydrogen chloride, HCl(g), react to form solid ammonium chloride, NH4Cl(s):
NH3(g) + HCl(g) → NH4Cl(s)
Two 2.50 L flasks at 30.0 oC are connected by a stopcock, as shown in the drawing
One flask contains 5.60g NH3(g), and the other contains 4.60 g HCl(g). When the stopcock is opened, the gases react until one is completely consumed.
Which gas will remain in the system after the reaction is complete?
Practice Problems
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