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Problem: Consider the combustion reaction between 26.0 mL of liquid methanol (density = 0.850 /mL) and 13.0 L of oxygen gas measured at STP. The products of the reaction are CO2(g) and H2O(g). Calculate the volume of liquid H2O formed if the reaction goes to completion and you condense the water vapor.

FREE Expert Solution

CH3OH (l) + 2 O2 (g) → 2 H2O (l) + CO2 (g)


Step 1

from methanol

26.0 mLCH3OH ×0.850 g CH3OH1 mL CH3OH×1 mol CH3OH32.042 g CH3OH×2 mol H2O1 mol CH3OH

= 1.38 mol H2O


from oxygen gas

n = PVRTn = (1 atm)(13.0 L)(0.08206 atm·Lmol·K)(273.15 K)n = 0.58 mol O2×2 mol H2O2 mol O2

n = 0.58 mol H2O


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Problem Details

Consider the combustion reaction between 26.0 mL of liquid methanol (density = 0.850 /mL) and 13.0 L of oxygen gas measured at STP. The products of the reaction are CO2(g) and H2O(g). Calculate the volume of liquid H2O formed if the reaction goes to completion and you condense the water vapor.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gas Stoichiometry concept. If you need more Gas Stoichiometry practice, you can also practice Gas Stoichiometry practice problems.