Step 1

*$\mathbf{h}\mathbf{}\mathbf{=}\mathbf{}\mathbf{10}\mathbf{.}\mathbf{3}\mathbf{}\overline{)\mathbf{cm}}\mathbf{}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\overline{)\mathbf{m}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{cm}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mm}}{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{m}}}$ ***= 103 mm**

If the atmospheric pressure is 0.980 atm , what is the pressure of the enclosed gas in each of the three cases depicted in the drawing ?

What is the pressure of the enclosed gas in (iii)? Assume that the gray liquid is mercury.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

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