Step 1

*$\mathbf{h}\mathbf{}\mathbf{=}\mathbf{}\mathbf{10}\mathbf{.}\mathbf{3}\mathbf{}\overline{)\mathbf{cm}}\mathbf{}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\overline{)\mathbf{m}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{cm}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mm}}{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{m}}}$ ***= 103 mm**

If the atmospheric pressure is 0.980 atm , what is the pressure of the enclosed gas in each of the three cases depicted in the drawing ?

What is the pressure of the enclosed gas in (iii)? Assume that the gray liquid is mercury.

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