# Problem: In Sample Exercise 10.16 in the textbook, we found that one mole of Cl2 confined to 22.41 L at 0 oC deviated slightly from ideal behavior. Calculate the pressure exerted by 1.00 mol  Cl2 confined to a smaller volume, 6.00 L , at 25 oC.Use van der Waals equation for your calculation. (Values for the van der Waals constants are a = 6.49 L2atm/mol2, b = 0.0562 L/mol.)

###### FREE Expert Solution

We’re being asked to calculate the pressure exerted by one mole of chlorine, Cl2 gas using the Van der Waal’s equation

The Van der Waals equation is shown below:

$\overline{)\left(\mathbf{P}\mathbf{+}\mathbf{a}\frac{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{V}}^{\mathbf{2}}}\right)\left(\mathbf{V}\mathbf{-}\mathbf{n}\mathbf{b}\right){\mathbf{=}}{\mathbf{n}}{\mathbf{R}}{\mathbf{T}}}$

P = pressure, atm
V = volume, L
n = # of moles, mol
R = gas constant = 0.08206 (Latm)/(molK)
T = temperature, K
a = polarity coefficient
= size coefficient

Let’s first isolate the pressure in the Van der Waals Equation:

81% (322 ratings) ###### Problem Details

In Sample Exercise 10.16 in the textbook, we found that one mole of Cl2 confined to 22.41 L at 0 oC deviated slightly from ideal behavior. Calculate the pressure exerted by 1.00 mol  Cl2 confined to a smaller volume, 6.00 L , at 25 oC.

Use van der Waals equation for your calculation. (Values for the van der Waals constants are a = 6.49 L2atm/mol2, b = 0.0562 L/mol.)