Problem: A mixture containing 0.768 mol  He(g), 0.286 mol Ne(g), and 0.116 mol  Ar(g) is confined in a 10.00-L vessel at 25 oC.Calculate the partial pressure of Ar in the mixture.

FREE Expert Solution

PV=nRT

P = pressure, atm
V = volume, L
n = moles, mol
R = gas constant = 0.08206 (L·atm)/(mol·K)
T = temperature, K

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Problem Details

A mixture containing 0.768 mol  He(g), 0.286 mol Ne(g), and 0.116 mol  Ar(g) is confined in a 10.00-L vessel at 25 oC.

Calculate the partial pressure of Ar in the mixture.

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