Problem: C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l), Δ;;;;;;H = –2803 kJBased on the enthalpy of the above reaction, what is the fuel value of glucose on a per gram basis?

FREE Expert Solution

Fuel value = kJ/g

MM of glucose is 180.16 g/mol

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C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l), ΔH = –2803 kJ

Based on the enthalpy of the above reaction, what is the fuel value of glucose on a per gram basis?

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