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Problem: Use bond enthalpies in the table below to estimate ΔHrxn for each of the following reactions.Average Bond Enthalpies (kJ/mol)C-H 413N-H 391O-H 463F-F 155C-C 348N-N 163O-O 146C=C 614N-O 201O=O 495Cl-F 253C-N 293N-F 272O-F 190Cl-Cl 242C-O 358N-Cl 200O-Cl 203Br-F 237C=O 799N-Br 243O-I 234Br-Cl 218C-F 485H-H 436Br-Br 193C-Cl 328H-F 567C-Br 276H-Cl 431I-Cl 208C-I 240H-Br 366I-Br 175H-I 299I-I 151

🤓 Based on our data, we think this question is relevant for Professor Wu's class at OSU.

FREE Expert Solution

We are asked to calculate the enthalpy of reactions (ΔHrxn).


To calculate the ΔH°rxn using bond energies, we’re going to use the following equation:

Hrxn=Hbond reactant-Hbond products


REACTION:

CHBr3 plus Cl2 goes to CClBr3 plus HCl.


Average Bond Enthalpies (kJ/mol)

C-H 413N-H 391O-H 463F-F 155
C-C 348N-N 163O-O 146
C=C 614N-O 201O=O 495Cl-F 253
C-N 293N-F 272O-F 190Cl-Cl 242
C-O 358N-Cl 200O-Cl 203Br-F 237
C=O 799N-Br 243O-I 234Br-Cl 218
C-F 485H-H 436
Br-Br 193
C-Cl 328H-F 567

C-Br 276H-Cl 431
I-Cl 208
C-I 240H-Br 366
I-Br 175

H-I 299
I-I 151












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Problem Details

Use bond enthalpies in the table below to estimate ΔHrxn for each of the following reactions

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Average Bond Enthalpies (kJ/mol)

C-H 413N-H 391O-H 463F-F 155
C-C 348N-N 163O-O 146
C=C 614N-O 201O=O 495Cl-F 253
C-N 293N-F 272O-F 190Cl-Cl 242
C-O 358N-Cl 200O-Cl 203Br-F 237
C=O 799N-Br 243O-I 234Br-Cl 218
C-F 485H-H 436
Br-Br 193
C-Cl 328H-F 567

C-Br 276H-Cl 431
I-Cl 208
C-I 240H-Br 366
I-Br 175

H-I 299
I-I 151



CHBr3 plus Cl2 goes to CClBr3 plus HCl.