Ch.6 - Thermochemistry WorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: The heat of combustion of fructose, C6 H12 O6, is -2812 kJ/mol.If a fresh golden delicious apple weighing 4.26 oz (121 g ) contains 17.0 g of fructose, what caloric content does the fructose contribut

Problem

The heat of combustion of fructose, C6 H12 O6, is -2812 kJ/mol.

If a fresh golden delicious apple weighing 4.26 oz (121 g ) contains 17.0 g of fructose, what caloric content does the fructose contribute to the apple?

Solution

We’re being asked to determine the caloric content fructose contributes to the apple.


The caloric content of food is determined from its enthalpy of combustion per gram, as measured in a bomb calorimeter.


The ΔHcomb described in joules (or kilojoules) are negative for all substances that can be burned. In contrast, the caloric content of a food is always expressed as a positive number because it is stored energy. So,


caloric content = - Hcomb


We will solve the problem by converting the enthalpy of combustion to calorie and determine the contribution of the fructose. 

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