# Problem: You may want to reference (Pages 165 - 166) Section 5.1 while completing this problem.Calculate the gravitational force of attraction for two protons separated by 76.0 pm. The mass of a proton is mp = 1.673 x 10–27 kg.Use the following equations: Fg = G(m1m2/d2), where G (gravitational constant) = 6.674 x 10–11 N m2/kg2

###### FREE Expert Solution

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{{\mathbf{Gm}}_{\mathbf{1}}{\mathbf{m}}_{\mathbf{2}}}{{\mathbf{d}}^{\mathbf{2}}}}$

###### Problem Details

You may want to reference (Pages 165 - 166) Section 5.1 while completing this problem.

Calculate the gravitational force of attraction for two protons separated by 76.0 pm. The mass of a proton is mp = 1.673 x 10–27 kg.

Use the following equations: Fg = G(m1m2/d2), where G (gravitational constant) = 6.674 x 10–11 N m2/kg2