$\overline{){{\mathbf{F}}}_{{\mathbf{el}}}{\mathbf{=}}{{\mathbf{k}}}_{{\mathbf{e}}}\mathbf{\left(}\frac{{\mathbf{Q}}_{\mathbf{1}}{\mathbf{Q}}_{\mathbf{2}}}{{\mathbf{d}}^{\mathbf{2}}}\mathbf{\right)}}$

You may want to reference (Pages 165 - 166) Section 5.1 while completing this problem.

Calculate the electrostatic force of repulsion for two protons separated by 76.0 pm. The charge of a proton is q = 1.6 x 10^{–19} C.

Use the following equation: F_{el} = k_{e}(Q_{1}Q_{2}/d^{2}), where k_{e} = 8.99 x 10^{9} N m^{2} / C^{2}

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