E → electrostatic potential energy

$\overline{)\mathbf{W}\mathbf{=}{\mathbf{E}}_{\mathbf{final}}\mathbf{-}{\mathbf{E}}_{\mathbf{initial}}}$

$\overline{)\mathbf{E}\mathbf{=}{\mathbf{k}}_{\mathbf{e}}\frac{{\mathbf{Q}}_{\mathbf{1}}\mathbf{\xb7}{\mathbf{Q}}_{\mathbf{2}}}{\mathbf{d}}}$

Initially, distance of 0.40 nm:

1 nm = 10^{-9} m

$\mathbf{d}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{40}\mathbf{}\overline{)\mathbf{nm}}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{9}}\mathbf{}\mathbf{m}}{\mathbf{1}\mathbf{}\overline{)\mathbf{nm}}}$

**d = 4.0x10 ^{-10} m**

You may want to reference (Pages 165 - 166) Section 5.1 while completing this problem.

A magnesium ion, Mg^{2+}, with a charge of 3.2x10^{-19} C and an oxide ion, O^{2-}, with a charge of -3.2x10^{-19} C, are separated by a distance of 0.40 nm. How much work would be required to increase the separation of the two ions to an infinite distance?

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