$\overline{){\mathbf{F}}{\mathbf{=}}\frac{{\mathbf{Gm}}_{\mathbf{1}}{\mathbf{m}}_{\mathbf{2}}}{{\mathbf{d}}^{\mathbf{2}}}}$

The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = k_{e}(Q_{1}Q_{2}/d^{2}) where k_{e} = 8.99 x 10^{9} N m^{2}/C^{2}, Q_{1} and Q_{2} are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q_{1} and Q_{2} will have the magnitude 1.60 x 10^{–19} C.

The force of gravity acting between two objects is given
by the equation F = G(m_{1}m_{2}/d^{2}), where G is the gravitational constant, G = 6.674 10^{-11} N m^{2}/kg^{2}, m_{1} and m_{2} are the masses of the two objects, and d is the distance separating them. What is the gravitational force of attraction (in Newtons) between the electron and proton?

Use the same distance: 1.3 x 10^{2} pm. Mass of an electron, m_{e} = 9.109 x 10^{–31} kg, mass of a proton, m_{p} = 1.673 x 10^{-27} kg.

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