# Problem: The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C.The force of gravity acting between two objects is given by the equation F = G(m1m2/d2), where G is the gravitational constant, G = 6.674 10-11 N m2/kg2, m1 and m2 are the masses of the two objects, and d is the distance separating them. What is the gravitational force of attraction (in Newtons) between the electron and proton?Use the same distance: 1.3 x 102 pm. Mass of an electron, me = 9.109 x 10–31 kg, mass of a proton, mp = 1.673 x 10-27 kg.

###### FREE Expert Solution

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{{\mathbf{Gm}}_{\mathbf{1}}{\mathbf{m}}_{\mathbf{2}}}{{\mathbf{d}}^{\mathbf{2}}}}$

84% (27 ratings) ###### Problem Details

The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C.

The force of gravity acting between two objects is given by the equation F = G(m1m2/d2), where G is the gravitational constant, G = 6.674 10-11 N m2/kg2, m1 and m2 are the masses of the two objects, and d is the distance separating them. What is the gravitational force of attraction (in Newtons) between the electron and proton?

Use the same distance: 1.3 x 102 pm. Mass of an electron, me = 9.109 x 10–31 kg, mass of a proton, mp = 1.673 x 10-27 kg.