Problem: The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C.The force of gravity acting between two objects is given by the equation F = G(m1m2/d2), where G is the gravitational constant, G = 6.674 10-11 N m2/kg2, m1 and m2 are the masses of the two objects, and d is the distance separating them. What is the gravitational force of attraction (in Newtons) between the electron and proton?Use the same distance: 1.3 x 102 pm. Mass of an electron, me = 9.109 x 10–31 kg, mass of a proton, mp = 1.673 x 10-27 kg.

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F=Gm1m2d2

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The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C.

The force of gravity acting between two objects is given by the equation F = G(m1m2/d2), where G is the gravitational constant, G = 6.674 10-11 N m2/kg2, m1 and m2 are the masses of the two objects, and d is the distance separating them. What is the gravitational force of attraction (in Newtons) between the electron and proton?

Use the same distance: 1.3 x 102 pm. Mass of an electron, me = 9.109 x 10–31 kg, mass of a proton, mp = 1.673 x 10-27 kg.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Coulomb's Law concept. If you need more Coulomb's Law practice, you can also practice Coulomb's Law practice problems.