$\overline{)\frac{{\mathbf{F}}_{\mathbf{elec}}}{{\mathbf{F}}_{\mathbf{gravity}}}}$

$\overline{){{\mathbf{F}}}_{{\mathbf{elec}}}{\mathbf{=}}\frac{{\mathbf{kq}}_{\mathbf{1}}{\mathbf{q}}_{\mathbf{2}}}{{\mathbf{r}}^{\mathbf{2}}}}$

$\overline{){{\mathbf{F}}}_{{\mathbf{gravity}}}{\mathbf{=}}{\mathbf{G}}\frac{{\mathbf{m}}^{\mathbf{2}}}{{\mathbf{r}}^{\mathbf{2}}}}$

The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = k_{e}(Q_{1}Q_{2}/d^{2}) where k_{e} = 8.99 x 10^{9} N m^{2}/C^{2}, Q_{1} and Q_{2} are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q_{1} and Q_{2} will have the magnitude 1.60 x 10^{–19} C. How many times larger is the electrostatic force of attraction than the force of gravity?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Coulomb's Law concept. If you need more Coulomb's Law practice, you can also practice Coulomb's Law practice problems.