# Problem: The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C. What is the electrostatic force of attraction (in Newtons) between an electron and a proton that are separated by 1.3 x 102 pm?

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###### FREE Expert Solution

$\overline{)\mathbf{F}\mathbf{=}{\mathbf{k}}_{\mathbf{e}}\frac{{\mathbf{Q}}_{\mathbf{1}}\mathbf{·}{\mathbf{Q}}_{\mathbf{2}}}{{\mathbf{d}}^{\mathbf{2}}}}$

1 pm = 10-12 m

d = 1.3x10-10 m ###### Problem Details

The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C. What is the electrostatic force of attraction (in Newtons) between an electron and a proton that are separated by 1.3 x 102 pm?