Problem: The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C. What is the electrostatic force of attraction (in Newtons) between an electron and a proton that are separated by 1.3 x 102 pm?

🤓 Based on our data, we think this question is relevant for Professor Haubrich's class at UNR.

FREE Expert Solution

F=keQ1·Q2d2

1 pm = 10-12 m

d=1.3×102 pm×10-12 m1 pm

d = 1.3x10-10 m


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Problem Details

The electrostatic force (not energy) of attraction between two oppositely charged objects is given by the equation F = ke(Q1Q2/d2) where ke = 8.99 x 109 N m2/C2, Q1 and Q2 are the charges of the two objects in Coulombs, and d is the distance separating the two objects in meters. The charges Q1 and Q2 will have the magnitude 1.60 x 10–19 C. What is the electrostatic force of attraction (in Newtons) between an electron and a proton that are separated by 1.3 x 102 pm?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Coulomb's Law concept. If you need more Coulomb's Law practice, you can also practice Coulomb's Law practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Haubrich's class at UNR.