We’re being asked to describe how you would prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0x108 bacteria.
Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters).
In other words:
For this problem, we're going to do the following steps:
Step 1: Calculate how many molecules of Calicheamicin gamma-1 is needed.
Step 2: Calculate the volume need from the stock solution.
Calicheamicin gamma-1, C55H74IN3O21S4, is one of the most potent antibiotics known: One molecule kills one bacterial cell.
Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0x108 bacteria, starting from a 5.00x10-9 M stock solution of the antibiotic. Complete the explanation.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Molarity concept. You can view video lessons to learn Molarity. Or if you need more Molarity practice, you can also practice Molarity practice problems.
What is the difficulty of this problem?
Our tutors rated the difficulty ofCalicheamicin gamma-1, C55H74IN3O21S4, is one of the most po...as medium difficulty.
How long does this problem take to solve?
Our expert Chemistry tutor, Sabrina took 5 minutes and 3 seconds to solve this problem. You can follow their steps in the video explanation above.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Moy's class at UNC.