Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5 10-9 M, and 1.00 mL of this solution will be delivered to a dish containing 2.0 x 105 cance

Solution: A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5 10-9 M, and 1.00 mL of this solution will be delivered to a dish containing 2.0 x 105 cance

Problem

A medical lab is testing a new anticancer drug on cancer cells. The drug stock solution concentration is 1.5 10-9 M, and 1.00 mL of this solution will be delivered to a dish containing 2.0 x 105 cancer cells in 5.00 mL of aqueous fluid.

What is the ratio of drug molecules to the number of cancer cells in the dish?

Solution
  • Calculate for the number of molecules using the given Molarity and volume and then Avogadro's number.
  • Recall that molarity: 

  • Dimensional analysis will appear as:

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