$\overline{)\mathbf{molarity}\mathbf{}\mathbf{\text{(M)}}\mathbf{=}\frac{\mathbf{mol}}{\mathbf{L}}}$

**Calculate moles MCHM:**

molar mass MCHM = 128.24 g/mol

$\mathbf{moles}\mathbf{}\mathbf{MCHM}\mathbf{=}\mathbf{7500}\mathbf{}\overline{)\mathbf{gallon}}\mathbf{\times}\frac{\mathbf{3}\mathbf{.}\mathbf{785}\mathbf{}\overline{)\mathbf{L}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{gallon}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{L}}}\phantom{\rule{0ex}{0ex}}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{\times}\frac{\mathbf{0}\mathbf{.}\mathbf{9074}\mathbf{}\overline{)\mathbf{g}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mol}}{\mathbf{128}\mathbf{.}\mathbf{24}\mathbf{}\overline{)\mathbf{g}}}$

**moles MCHM = 200864.1415 mol**

**Calculate the volume of the first part of the river:**

$\overline{)\mathbf{V}\mathbf{=}\mathbf{l}\mathbf{\times}\mathbf{w}\mathbf{\times}\mathbf{h}}$

convert units to cm:

In 2014, a major chemical leak at a facility in West Virginia released 7500 gallons of MCHM (4-methylcyclohexylmethanol, C_{8}H_{16}O) into the Elk River. The density of MCHM is 0.9074 g/mL.

Calculate the initial molarity of MCHM in the river, assuming that the first part of the river is 7.10 feet deep, 100.0 yards wide, and 100.0 yards long. 1 gallon = 3.785 L.

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